[-(2+i)][x-(2-i)]=0

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Solution for [-(2+i)][x-(2-i)]=0 equation: 


Simplifying
[-1(2 + i)][x + -1(2 + -1i)] = 0
[(2 * -1 + i * -1)][x + -1(2 + -1i)] = 0
[(-2 + -1i)][x + -1(2 + -1i)] = 0
[-2 + -1i][x + (2 * -1 + -1i * -1)] = 0
[-2 + -1i][x + (-2 + 1i)] = 0

Reorder the terms:
[-2 + -1i][-2 + 1i + x] = 0

Multiply [-2 + -1i] * [-2 + 1i + x]
[-2[-2 + 1i + x] + -1i * [-2 + 1i + x]] = 0
[[-2 * -2 + 1i * -2 + x * -2] + -1i * [-2 + 1i + x]] = 0
[[4 + -2i + -2x] + -1i * [-2 + 1i + x]] = 0
[4 + -2i + -2x + [-2 * -1i + 1i * -1i + x * -1i]] = 0

Reorder the terms:
[4 + -2i + -2x + [2i + -1ix + -1i2]] = 0
[4 + -2i + -2x + [2i + -1ix + -1i2]] = 0

Reorder the terms:
[4 + -2i + 2i + -1ix + -1i2 + -2x] = 0

Combine like terms: -2i + 2i = 0
[4 + 0 + -1ix + -1i2 + -2x] = 0
[4 + -1ix + -1i2 + -2x] = 0

Solving
4 + -1ix + -1i2 + -2x = 0

Solving for variable 'i'.

The solution to this equation could not be determined.

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